Question

3x + 3y + 2z = –5
x + y + 3z = –4
2x + 2y + 5z = –7

Solve this system of equations

Answer 1

Can you use matrices?

Answer 2

rref{{3,3,2,–5},{1,1,3,-4},{2,2,5,-7}}

then read the right column

Answer 3

lol ... i can use matrixes ;)

Answer 4

http://www.wolframalpha.com/input/?i=rref%7B%7B3%2C3%2C2%2C%E2%80%935%7D%2C%7B1%2C1%2C3%2C-4%7D%2C%7B2%2C2%2C5%2C-7%7D%7D

infinite solutions; the bottom row is all zeros so there is no single solution to be had

Answer 5

(–4, –3, 1)

(–4, 3, –1)

(4, –3, –1)

(–4, –3, –1)

Answer 6

you must have a typo

Answer 7

Nope. It's one of those choices

Answer 8

then the solutions will fit this format:

|-1| |-1|
| 0 |+ | 1| t
|-1| | 0|

Answer 9

You are going to have at least one free variable you can note this right away when the first two columns are scalar multiples of each other.

Answer 10

Because there is at least one free variable then there can be an infinite solutions or no solution at all.

Answer 11

since there is no way to math out a single solution; your best effort will be trial and error