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Mathematics 15 Online
OpenStudy (anonymous):

In text it says that a function is a collection of pairs of numbers with the following property: if (a,b) & (a,c) are both in the collection, then b=c; in other words, the collection must not contain two different pairs with the same first element. Now in an other text I found that if b is a range of the function then it could have several preimages or no preimages at all (preimage means the domain) now these two definitions are opposite to each other & I don't really know that which one is true :|

OpenStudy (anonymous):

@experimentX any clue?

OpenStudy (anonymous):

the first definition is from Spivak's Calculus & the second is from Kolmogorov's Analysis

OpenStudy (experimentx):

A function is defined as a relation such that an element on pre-image can have only one element on range set. now a is the preimage, then it can have only one element, ie, f(a) = b and f(a) = c , if f is function then b = c.

OpenStudy (experimentx):

on the other hand, some elements on the range set can have two or more than two preimages for example: - f(x) = x^2 can have -2 and +2 for domain and +4 for range.

OpenStudy (anonymous):

okkkkkkkkkkkkkkkkkk so both definitions are actually true

OpenStudy (anonymous):

got it thanks buddy @experimentX

OpenStudy (experimentx):

also let us consider two sets of integers |dw:1334785505302:dw|

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