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x^2+12x+36 perfect square ?
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i put (x+6)(x-6) but didnt work out
x^2+12x+36 x^2+6x+6x+36 ... Note: 6 and 6 add to 12 and multiply to 36 (x^2+6x)+(6x+36) x(x+6)+6(x+6) (x+6)(x+6) (x+6)^2 So it is a perfect square
oh, i thought i had to have one + and one minus? is that not the case?
(x+6)(x-6) gives you x^2-36 (it's a difference of squares)
(x+6)(x-6) = x^2 - 36 Difference of squares. Not the expression you have in this case.
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you're thinking of a difference of squares, which is binomial (ie has two terms)
okay phew. got cha :)
(a+b)^2 = a^2 + 2ab + b^2 (a-b)^2 = a^2 - 2ab + b^2 (a+b)(a-b) = a^2 - b^2
thanks ^_^
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