Question

How do I calculate the excess reagent of this balanced chemical reaction: AgNO3(aq)+ NaCl(aq) -> AgCl(s) + NaNO3(aq)

Answer 1

AgNO3(aq)+ NaCl(aq) -> AgCl(s) + NaNO3(aq)
n =7.68 x 10-4 mol m = 0.11g
C= 0.1536 M n=7.68 x 10-4 mol

*reactant

Answer 2

0,1536 is concentration from AgNO3? and ) 0.11 g is mass of NaCl? 7.68 x 10-4 is moles of both AgNo3 and NaCl?

Answer 3

i think u should convert reagent into moles..if moles of AgNO3 is bigger than moles of NaCl the excess reaction is \[ moles AgNO3- moles NaCl\] if NaCl is bigger, do it reverse.

Answer 4

just because have more moles of something doesnt mean it yields more product. go from molar mass to moles and then moles of product. if the moles of the product are larger, the reactant you used it the excess reactant.