Question

improper integral: integral of x(e^(-x^2))dx.
does it diverge or converge?

Answer 1

@eliassaab help please:)

Answer 2

\[\int_{-infty}^{infinity}{x e^{-x^2}dx}\]

?

Answer 3

ya

Answer 4

Converges

Answer 5

please explain(and to what

Answer 6

∫xe−x2dx=−(1/2)e−x2

Answer 7

yuck. I tried to fix my answer and now it looks worse. :-/
I meant ∫x e^−x^2dx=−(1/2)e^−x^2

Answer 8

Now you can take the limit as x approaches infinity.

Answer 9

I like paul's notes:

Answer 10

zero?