given cos x =-2/5 and cot x >0 find csc x, sin x, tan x, cot x
So, this is probably best approached as a logical problem. cos x = -2/5 will correspond to two angles. One of which will have yield a positive sin x, and the other will yield a negative sin x. After you find this, you just need to use the definitions of the other functions to find their values.
Thanks, but based on the fact that the cot is >0, then we have one angle in quadrant 3. I got the answers cscx= \[-5\sqrt{21}/21\], sinx= \[-\sqrt{21}/5\], tanx=\[-\sqrt{21}/2\], and \[-2\sqrt{21}/21\]but the teacher marked all my signs wrong which I don't understand as in the third quadrant both sin and cos are negative
Since Cot x > 0 and cos x is negative, sin x has to be negative as well, meaning csc x will be negative, tan x will be positive, and cot x will be positive.
Do you see why that is?
yes, that is what I thought and your answer matches mine above... but the teacher marked it wrong and took points off my exam... thanks for your help!
I put the teacher's answers above... mine were correct...
Very interesting. Even teachers make mistakes, try talking to him/her!
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