Given vector v with initial point: (-6,4,-2) and terminal point: (1,-1,3) Find a unit vector in the direction of v.
last - start gives you directionality
divide by length to get it to unit length
3ft/3 = 1 12 inches/12 = 1 58 miles /58 = 1 \[\left|\frac{\vec v}{|v|}\right|=1\]
My teacher gave the answer sqrt(11)/33 (7,-5,5) how would I get that (this was on a test I failed, I just want to know how to do it right)
<1-(-6),-1-4,3-(-2)>=<7,-5,5> which is the vector. To find it's magnitude you do \[\sqrt{7^{2}+-5^{2}+5^{2}}\]
a unit vector is the (vector/mag of the vector)
That makes sense. I didn't know what to find the magnitude of
Although the mag is 3(11^1/2)
Yeah that's what I got too. Not sure how to get (11^1/2)/33
I would mention that to him so you can get your points back on the exam!
I'll ask tomorrow, but wont get any points back since I don't even know why I tried doing, but it was nowhere near the right answer. thanks for the help though :)
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