Question

what is the derivative of y=sinxtanx

Answer 1

use the product rule:\[\frac{d}{dx}(u v) = v \frac{du}{dx}+u \frac{dv}{dx}\]where:\[u = \sin(x)\]and:\[v = \tan(x)\]

Answer 2

is the answer
y'=(cosx*tanx)(sec^x*sinx)

Answer 3

no

Answer 4

sorry + in the middle

Answer 5

both terms are added not multiplied.

Answer 6

what do you mean by "sec^x" ?

Answer 7

squared