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Find the number of positive real zeros of f(x)=-7x^4+49x^3+84x^2
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you sure is +84 or -84?
I think it's +
if + you cant get the roots, i'll just assume its -
ok :) thanks
\[-7x^4+49x^3-84x^2\] Factor the x^2 out \[x^2(-7x^2+49x-84)\] \[x^2(x-3)(x-4)\] Set it =0 to find the roots, \[(x^2)(x-3)(x-4)=0\] Set each brackets =0, x^2=0 x-3=0 x-4=0 x=0 x=3 x=4
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the descartes rule of signs gives us that there is 1 positive root since ther eis only 1 sign change in the eqs positive position
its not asking for the roots; just the number of roots that are positive in value
..and obama ate a dog :/
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