Question

Find X, and Y, picture attached

Answer 1

#4

Answer 2

\[x = 15*\sqrt{2} * \cos(45^{o}) = 15*\sqrt{2} * \sqrt{2} / 2 = 15\]
and \[y = 15*\sqrt{2} * \sin(45^{o}) = 15*\sqrt{2} * \sqrt{2} / 2 = 15\]

Answer 3

so the answer is 15 for both?

Answer 4

its a 45-45-90 triangle so x and y are the same length:

so x = y

lets use the Pythagorean Theorem:

\[(15\sqrt{2})^2 = x^2 + y^2 \]
since x = y, we can plug one in
\[(15\sqrt{2})^2 = x^2 + x^2 \]
\[(15\sqrt{2})^2 = 2x^2 \]\[225(2) = 2x^2\]
\[550 = 2x^2\]
\[225 = x^2\]

x = 15

since x = y, then y = 15

Answer 5

okay, thanks I understand now