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OpenStudy (anonymous):
http://i.imgur.com/1u0QE.png
http://i.imgur.com/WJ6wt.png
Can anyone teach me how I go about solving this?
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OpenStudy (anonymous):
Okay I figured out the second one myself but I'm still having problem with the first one
OpenStudy (anonymous):
your job is to add right? i think you need partial fractions for this one
OpenStudy (anonymous):
Okay I did partial fraction and god B = 1 and A = -1
What do I do next?
OpenStudy (anonymous):
you get \(\frac{2}{(n+2)(n+4)}=\frac{1}{n+2}-\frac{1}{n+4}\) a nice telescoping sum
OpenStudy (anonymous):
so i think what you need is to find the first two terms that do not get killed off later
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OpenStudy (anonymous):
you good from there?
OpenStudy (anonymous):
is the answer 3/4?
OpenStudy (anonymous):
no i get \(\frac{7}{12}\)
OpenStudy (anonymous):
start replacing n by 1, 2, 3, 4, ... and see what you get
OpenStudy (anonymous):
everything else cancels out except (1/2) and (1/4)..am I doing something wrong..
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OpenStudy (anonymous):
oops I see my mistake
OpenStudy (anonymous):
whew
i got everthing but \(\frac{1}{3}\) and \(\frac{1}{4}\)
OpenStudy (anonymous):
yeah thanks! :)
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