Ask your own question, for FREE!
Mathematics 13 Online
OpenStudy (anonymous):

http://i.imgur.com/1u0QE.png http://i.imgur.com/WJ6wt.png Can anyone teach me how I go about solving this?

OpenStudy (anonymous):

Okay I figured out the second one myself but I'm still having problem with the first one

OpenStudy (anonymous):

your job is to add right? i think you need partial fractions for this one

OpenStudy (anonymous):

Okay I did partial fraction and god B = 1 and A = -1 What do I do next?

OpenStudy (anonymous):

you get \(\frac{2}{(n+2)(n+4)}=\frac{1}{n+2}-\frac{1}{n+4}\) a nice telescoping sum

OpenStudy (anonymous):

so i think what you need is to find the first two terms that do not get killed off later

OpenStudy (anonymous):

you good from there?

OpenStudy (anonymous):

is the answer 3/4?

OpenStudy (anonymous):

no i get \(\frac{7}{12}\)

OpenStudy (anonymous):

start replacing n by 1, 2, 3, 4, ... and see what you get

OpenStudy (anonymous):

everything else cancels out except (1/2) and (1/4)..am I doing something wrong..

OpenStudy (anonymous):

oops I see my mistake

OpenStudy (anonymous):

whew i got everthing but \(\frac{1}{3}\) and \(\frac{1}{4}\)

OpenStudy (anonymous):

yeah thanks! :)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!