Question

(-39x^-2y/156x3y^-3)^3

Answer 1

156x^3y^-3

Answer 2

\[\large \mathbf{(\frac{-39x^{-2}y}{156x^{3}y^{-3}})^{3}}\]

a nice first step would be to turn those negative exponents to positive...

\[\large \mathbf{(\frac{-39(y^{3})(y)}{156(x^{3})(x^{2})})^{3}}\]

Answer 3

multiply by 1 to make them positive?

Answer 4

no..put it in the numerator/denominator...for example x^-2 = 1/x^2
1/y^-3 = y^3 got it? :)

Answer 5

no

Answer 6

aww. well x^-2 was in the numerator right? to make it positive you put it in the denominator..y^-3 was in the denominator so put it in numerator to make it positive..that's all there is to it..

Answer 7

oh lol