Question

(c^-3)(d^-2)/(c-4)(d-5) =
(c^-3)/(c^-4) x (d^-2)/(d^-5)
Where do i go from here?

Answer 1

\[\frac{\frac{1}{c^{3}d^{2}}}{(c-4)(c-5)}\]is this your question?

Answer 2

\[C(-3) \times D(-5) \over C(-4) \times D(-5)\]

Answer 3

thats the original question.

Answer 4

- so i think not is this ,i think there are missed the exponents signs ,i think that -4 and -5 are exponents too

Answer 5

(c^-3)(d^-2) 1/((c^3)(d^2)) 1 ((c^4)(d^5))
------------ = --------------- = ----------- * ------------ =
c^-4)(d^-5) 1/((c^4)(d^5)) ((c^3)(d^2)) 1

= c^(4-3)*d^(5-2) = c*d^3

Answer 6

the equation i wroe is exctly how it is in the book. the -4n -5 are not exponents.