(c^-3)(d^-2)/(c-4)(d-5) =
(c^-3)/(c^-4) x (d^-2)/(d^-5)
Where do i go from here?

Question

(c^-3)(d^-2)/(c-4)(d-5) = 
(c^-3)/(c^-4) x (d^-2)/(d^-5)
Where do i go from here?

anonymous · Answer

$$\frac{\frac{1}{c^{3}d^{2}}}{(c-4)(c-5)}$$is this your question?

anonymous · Answer

$$C(-3) \times D(-5) \over C(-4) \times D(-5)$$

anonymous · Answer

thats the original question.

jhonyy9 · Answer

- so i think not is this ,i think there are missed the exponents signs ,i think that -4 and -5 are exponents too

jhonyy9 · Answer

(c^-3)(d^-2)         1/((c^3)(d^2))              1               ((c^4)(d^5))
------------ = --------------- = ----------- * ------------ = 
c^-4)(d^-5)          1/((c^4)(d^5))        ((c^3)(d^2))               1

= c^(4-3)*d^(5-2) = c*d^3

anonymous · Answer

the equation i wroe is exctly how it is in the book. the -4n -5 are not exponents.