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Help solve.. 3/a+2/b=1/c
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Solve for?
A Sorry
in terms of b and c?
It just says solve for a..
\[\large \mathbf{\frac{3}{a} + \frac{2}{b} = \frac{1}{c}}\] right? hmmm..
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Yes
ok well then it shouldn't be that bad: the first thing we want to do it get anything with an "a" in it together. so we would do: 3/a= [(1/c) -(2/b)] The reason i put it in brackets is so that we traet the tire thing as one piece. then we do some cross multiplication and division: 3= [(1/c) -(2/b)]*a 3/[(1/c) -(2/b)] = a
This also can be simplified to get \[ a=\frac{3 b c}{b-2 c} \]
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