Help me please.
?
with what?
An Li projected a ball into the air at 32 feet per second from a platform 48 feet off the ground. The path of the ball is represented by the equation s(t) = -16tsquared + 32t + 48, where s is the height of the ball and t is the time, in seconds, after the ball was projected. How many seconds will it take the ball to reach the ground?
Answer choices: a - 1 b - 2 c - 3 d- 4 Please explain. ;3
set s(t) = 0
when ball is on the ground, height is 0.
try plugging in the answer in the variable and see if it matches up
^ or do that.
hahah it works ya know!
Oh s(t) = 0?
which one of those answers makes 0
For the t_squared do we actually have to square it
Im still confused...Im bad at math :/
same here but i try even though what your doing is beyond my level
After you set it to zero, what method are you pose to use?
like i said try plugging in the answer into the T and see what you get if which one will equal the zero=s(t)
Is 0 pose to = 0 when you get the right answer o-o
ok i got it the answer should be t=3
well, you're finding t, so s(t) = 0, find t.
Okie I get it just keep plugging Q~Q So much work. Ty.
no, don't just keep plugging in, it won't work in the future if it's not multiple choice.
Oh its for getting ready for cst
it's a waste of time on a test also.
only plugg in to find answer but eventualy youll need to work it out to get the answer you got
I dont gte how to find it by setting it to 0 tho
set it to 0, then isolate for t. what do you not get.
take your equation for the path of the ball, notice how everything in the equation is a mulitple of 16? we can take out that sixteen and get rid of it because we only want to know when your equation =0 your new equation: (-x^2 +2x +3)=0 we can factor this into (-x+3)(x+1)=0 the equation will be zero when either of these = 0 from this we can have 2 answers: one at x=-1 one at x=3 since time can't go backwards, the only answer we have left is at x=3
isnt there more than one t tho? so how do you isolate. o-o
yes, there is more than one t. if you look at my solution you will see that i have 2 "x"s that work, but one of them is negative, so we can't use it as a solution, because the ball can't go back in time
OMG. I cant believe I fogot that. Lol. My teacher taught me that three days ago...
Ty.
Np. Better than studying Calculus 4 like i should be
Im not in that grade tho. Lol.
forget grade, try university year
Lol.
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