Question

simplify the expression:
1+ sinx/cosx + cosx/1+ sinx
do i multiply by the opposite denominator?

Answer 1

>< KAWAII! your pic

Answer 2

@Kitsune ty ^^ <3

Answer 3

\[\large \mathbf{\frac{1+sinx}{cosx} + \frac{cosx}{1+sinx}}\]
^that's the problem right?

Answer 4

yup

Answer 5

hmmm..your problems are getting interesting >:)) gimme a sec..

Answer 6

okie dokie lol

Answer 7

Try multiplying the second term by the conjugate of the denominator

Answer 8

oooo i have it...give me a sec

Answer 9

2/cosx <--- most likely you will get this answer.

Answer 10

\[\frac{1+\sin(x)}{\cos(x)} + \frac{\cos(x)}{1+\sin(x)}\]
\[\frac{[1+\sin(x)]^{2}}{\cos(x)[1+\sin(x)]} + \frac{[\cos(x)]^{2}}{\cos(x)[1+\sin(x)]}\]
\[\frac{1+2\sin(x) + \sin ^{2}(x) + \cos ^{2}(x)}{\cos(x)[1+\sin(x)]}\]
\[\frac{2+2\sin(x)}{\cos(x)[1+\sin(x)]}\]
\[\frac{2[1+\sin(x)]}{\cos(x)[1+\sin(x)]}\]
\[\frac{2}{\cos(x)}\]

Answer 11

the answer supposed to be 2secx o.o i just checked my answer sheet

Answer 12

\[\sec(x) = \frac{1}{\cos(x)}\]
so 2/cos(x) = 2 * (1/cos(x)) or 2*sec(x) :P