Question

Consider the function f(x) = 2sin(x2) on the interval 0 ≤ x ≤ 3.

(a) Find the exact value in the given interval where an antiderivative, F, reaches its maximum.
x =



(b) If F(1) = 9, estimate the maximum value attained by F. (Round your answer to three decimal places.)
y ≈

Answer 1

set 2sin(x^2)=0

Answer 2

Wait, over an interval -_-

Answer 3

Ignore the interval, and just solve that trig equation.

Answer 4

i know that the answer for part "a" is

Answer 5

square(pi)

Answer 6

square or sqrt?

Answer 7

i dont know how to do part b

Answer 8

sqrt

Answer 9

Well, your interval s defined only up to 3. Is that supposed to be that way, or is the three suposed to be pi?

Answer 10

up to 3

Answer 11

a)\[2*\sin(2*x)=0\rightarrow x=k*pi/2\]
In this interval x=pi/2

Answer 12

Do you understand a though?

Answer 13

well i got x=