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Mathematics 8 Online
OpenStudy (anonymous):

Vectors. Please help!!!!!

OpenStudy (anonymous):

Study, check out what I said in the chat.

OpenStudy (anonymous):

Hrm? You should type up the entire question then.

OpenStudy (anonymous):

Yes what is the question?

OpenStudy (anonymous):

\(\ \ \huge What does this mean: \vec{u}_{\vec{w}} \). @kevo I'm in precalc. Not doing derivative stuff.

OpenStudy (anonymous):

Im given that vector v is (3,2) and w is (-2,5)

OpenStudy (anonymous):

@KingGeorge Vector Help!

OpenStudy (anonymous):

Have you learned in class about the dot product? Or what is the name of the section of the book where this question is found?

OpenStudy (anonymous):

Yes, we learned about the dot product and orthogonal today

OpenStudy (anonymous):

What should I do now? How am I supposed to solve this?

OpenStudy (anonymous):

Anyone?

OpenStudy (dumbcow):

are you multiplying the vectors? looks like vector subscript vector which is crazy

OpenStudy (kinggeorge):

I'm not actually sure what that notation means, but for now, I'll work off of the assumption that it represents vector projection.

OpenStudy (anonymous):

If it helps, I can post the WS that I am working on here...

OpenStudy (kinggeorge):

So you want to find the the projection of \(\vec u\) on \(\vec v\). To do this, there's a simply formula.\[\large \vec u_{\vec v}= {\vec u \cdot \vec v \over |v|^2}\;\; \vec v\]

OpenStudy (kinggeorge):

If you could post the worksheet, that might be helpful to give us an idea of what the notation probably means.

OpenStudy (anonymous):

If you want to find the dot product you have <3,2><-2,5>=(3)(-2)+(2)(5)=-6+10=4

OpenStudy (anonymous):

Vector subtraction!!! LOL You simply subtract the components LOL <3-2,-2-5>=<1,-7>

OpenStudy (anonymous):

Yes for that first one... But 3/4 are where Im confused

OpenStudy (dumbcow):

oh i just realized u is not a given vector, prob represents unit vector find unit vector of w

OpenStudy (anonymous):

Here's one with better quality

OpenStudy (anonymous):

Unit vector?

OpenStudy (kinggeorge):

I agree with dumbcow. That would make much more sense.

OpenStudy (anonymous):

Yes the unit vector!!! LOL You want to find a vector in the direction of the vector v with length 1 and you want to find a vector in the direction of w with length 1.

OpenStudy (anonymous):

? How do I do that?

OpenStudy (kinggeorge):

To find the unit vector of some vector \(\vec a\) use the following.\[{\vec a \over |\vec a|}\]where \(|\vec a|\) is the length of the vector.

OpenStudy (anonymous):

You simply divide the given vector by its length. You know how to find the length of a vector?

OpenStudy (anonymous):

Length of a given vector. Example: Vector v=<3,4>. Call u the unit vector in the direction of v. Then u= <3,4>/ sqrt(3^2 + 4^2)=<3,4>/sqrt(9+16)=<3,4>/5=<3/5,4/5> final answer is u=<3/5,4/5>

OpenStudy (anonymous):

So the length of a vector v=<a,b> is given by sqrt(a^2 + b^2)

OpenStudy (anonymous):

Okay I have another question.... So is the dot product the same as |dw:1334817256497:dw|? What's the difference? When do you use either

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