Vectors. Please help!!!!!
Study, check out what I said in the chat.
Hrm? You should type up the entire question then.
Yes what is the question?
\(\ \ \huge What does this mean: \vec{u}_{\vec{w}} \). @kevo I'm in precalc. Not doing derivative stuff.
Im given that vector v is (3,2) and w is (-2,5)
@KingGeorge Vector Help!
Have you learned in class about the dot product? Or what is the name of the section of the book where this question is found?
Yes, we learned about the dot product and orthogonal today
What should I do now? How am I supposed to solve this?
Anyone?
are you multiplying the vectors? looks like vector subscript vector which is crazy
I'm not actually sure what that notation means, but for now, I'll work off of the assumption that it represents vector projection.
If it helps, I can post the WS that I am working on here...
So you want to find the the projection of \(\vec u\) on \(\vec v\). To do this, there's a simply formula.\[\large \vec u_{\vec v}= {\vec u \cdot \vec v \over |v|^2}\;\; \vec v\]
If you could post the worksheet, that might be helpful to give us an idea of what the notation probably means.
If you want to find the dot product you have <3,2><-2,5>=(3)(-2)+(2)(5)=-6+10=4
Vector subtraction!!! LOL You simply subtract the components LOL <3-2,-2-5>=<1,-7>
Yes for that first one... But 3/4 are where Im confused
oh i just realized u is not a given vector, prob represents unit vector find unit vector of w
Here's one with better quality
Unit vector?
I agree with dumbcow. That would make much more sense.
Yes the unit vector!!! LOL You want to find a vector in the direction of the vector v with length 1 and you want to find a vector in the direction of w with length 1.
? How do I do that?
To find the unit vector of some vector \(\vec a\) use the following.\[{\vec a \over |\vec a|}\]where \(|\vec a|\) is the length of the vector.
You simply divide the given vector by its length. You know how to find the length of a vector?
Length of a given vector. Example: Vector v=<3,4>. Call u the unit vector in the direction of v. Then u= <3,4>/ sqrt(3^2 + 4^2)=<3,4>/sqrt(9+16)=<3,4>/5=<3/5,4/5> final answer is u=<3/5,4/5>
So the length of a vector v=<a,b> is given by sqrt(a^2 + b^2)
Okay I have another question.... So is the dot product the same as |dw:1334817256497:dw|? What's the difference? When do you use either
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