If you have an initial partial pressure of the reactant, temp and the partial pressure of the product at equilibrium how can you get Kp? Please do not post just the answer.

Question

anonymous · Answer

When a vessel initially containing 712  of  comes to equilibrium at 298 , the equilibrium partial pressure of X is 115 . The same reaction is repeated with an initial partial pressure of 710  of  at 756 ; the equilibrium partial pressure of X is 535 . For the general equation; $$X_{2(g)} \rightarrow 2X_{(g)}$$

anonymous · Answer

The goal is to use both Kp's to find Change in enthalpy.  I know how to find change in enthalpy if I have both Kp's but I don't know how to find Kp.

mos1635 · Answer

what is 712?
298 should be Kelvin
115is presure
initial partial pressure of 710 of at 756=??

mos1635 · Answer

if T,V constant ratio of moles =ratio of partial presuse
so we are allowed to calc in pressure

                         X2(g)→2X(g)
initial                  Po          0
reacts/produse    -P        +2P
equilibria             Po-P       2P

i think that your data refer to Po and 2P
but your typing is a litle condenced....:)

anonymous · Answer

pressures are in torr. Temp is in Kelvin. Sorry.

mos1635 · Answer

please copy paste and correct it so i wiil try to see if i can help...