simplify:

Question

simplify:

anonymous · Answer

$$Y=\frac{27s-9}{(9s^{2}-6s+1)}$$

anonymous · Answer

i get $$Y=\frac{9(3s-1)}{(s-\frac{1}{3})(s-\frac{1}{3})}$$

anonymous · Answer

but i dont think its in the simplified version

anonymous · Answer

oh wait

anonymous · Answer

I get y = 9 /3s -1

anonymous · Answer

kay ._. cant see the relationship at first.. LOL brain clogged

lgbasallote · Answer

ahh you know the numerator...but $\Large (\frac{1}{3})^{2}$ is not equal to 1 :P

anonymous · Answer

so it also equals to $$\frac{81}{3s-1}$$?

lgbasallote · Answer

81? no...remember you have  $\Large \frac{9(3s-1)}{(3s-1)(3s-1)}$

anonymous · Answer

because if i factor another 3 out from the numerator, i can cancel 1 term of (s-1/3) frm top and btm

anonymous · Answer

omg == brain clogged again

lgbasallote · Answer

$$\huge 9s^{2} - 6s + 1 \ne (s - \frac{1}{3})(s - \frac{1}{3})$$

anonymous · Answer

thr's a 9 outside of (s-1/3)(s-1/3)?

lgbasallote · Answer

wait...let's start from the beginning..there seems to be some confusion..

anonymous · Answer

laplace derivative clogging my brain ...

lgbasallote · Answer

first factor out the numerator.. (27s - 9)..we take 9 out..9(3s - 1)

$\Large \mathsf{good?}$

..wait is this laplace derivative?

anonymous · Answer

er is part of it, i need to simplify it b4 applying the inverse

anonymous · Answer

i think i know where i went wrong

anonymous · Answer

9s^2 -6s +1 is (3s-1)^2 == i wrote it as (s-1/3)^2

lgbasallote · Answer

yes! right :DDD