solve 2sin(2x)-cot(x)cos(x)=1-csc(x) I have: 2(2 sin(x)cos(x)-cos(x)/sin(x)*cos(x)+1/sin(x)-1 not sure if that is correct yet
just continuing from where you are right now.. \(\Large 2sinxcosx - \frac{cos^2x}{sinx} + \frac{1}{sinx} - 1 = 0\) btw...are you sure this is not proving??
im sure its solving
i would multiply by sin x
continuing from that...i'll group some terms...then tell me if you see something familiar (by that i mean if you get an idea on how to solve) \(\Large (2sinxcosx - 1) + (\frac {-cos^2x}{sinx} + \frac{1}{sinx}) = 0\) are you seeing something? or need i go on?
what happened to the 2 in the beginning?
hmm oh yeah..it's supposed to be 4sinxcosx then the rest
ok
lemme work it out, i'll show you in a min....if thats ok
sure :DDD
interesting problem btw..needs some imagination haha
my teacher is nutzzzo
lol =))) so...figured it out yet?
should i multiply by sin x?
multiply what by sinx?
the whole thing
get rid of the fractions
hmm...it works on rational fractions....go on..try
ok, so this is what i think i should have: \[\sin(x)(\sin(x)-1)=0 and \cos(x)+1=0\]
huh? why'd you separate 2 equations?
x=0 x=π x=π/2 x=2π/3
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