solve 2sin(2x)-cot(x)cos(x)=1-csc(x)
I have:
2(2 sin(x)cos(x)-cos(x)/sin(x)*cos(x)+1/sin(x)-1
not sure if that is correct yet
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OpenStudy (lgbasallote):
just continuing from where you are right now..
\(\Large 2sinxcosx - \frac{cos^2x}{sinx} + \frac{1}{sinx} - 1 = 0\)
btw...are you sure this is not proving??
OpenStudy (anonymous):
im sure its solving
OpenStudy (anonymous):
i would multiply by sin x
OpenStudy (lgbasallote):
continuing from that...i'll group some terms...then tell me if you see something familiar (by that i mean if you get an idea on how to solve)
\(\Large (2sinxcosx - 1) + (\frac {-cos^2x}{sinx} + \frac{1}{sinx}) = 0\)
are you seeing something? or need i go on?
OpenStudy (anonymous):
what happened to the 2 in the beginning?
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OpenStudy (lgbasallote):
hmm oh yeah..it's supposed to be 4sinxcosx then the rest
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
lemme work it out, i'll show you in a min....if thats ok
OpenStudy (lgbasallote):
sure :DDD
OpenStudy (lgbasallote):
interesting problem btw..needs some imagination haha
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OpenStudy (anonymous):
my teacher is nutzzzo
OpenStudy (lgbasallote):
lol =))) so...figured it out yet?
OpenStudy (anonymous):
should i multiply by sin x?
OpenStudy (lgbasallote):
multiply what by sinx?
OpenStudy (anonymous):
the whole thing
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OpenStudy (anonymous):
get rid of the fractions
OpenStudy (lgbasallote):
hmm...it works on rational fractions....go on..try
OpenStudy (anonymous):
ok, so this is what i think i should have:
\[\sin(x)(\sin(x)-1)=0 and \cos(x)+1=0\]