@thomas5267 Here comes your problem~

Question

callisto · Answer

attachment

anonymous · Answer

a4.59552
b63.56222585
c9.5251563639

thomas5267 · Answer

AE is $3\sqrt{12}$.

callisto · Answer

@wumbo All are incorrect
@thomas5267 Hmm.. not correct neither

thomas5267 · Answer

Isn't that point E bisects BC?

callisto · Answer

Yes

thomas5267 · Answer

Sorry, I type the wrong answer, it should be $12\sqrt{3}$.

callisto · Answer

Yes :)

callisto · Answer

Have to go now~ I'll come and check again tomorrow :)
Have fun!!!!

thomas5267 · Answer

$$
\begin{align*}
AD&=\sqrt{(12\sqrt{3})^2+6^2} \
AD&=6\sqrt{13}
\end{align*}
$$
$$
\begin{align*}
\frac{6\sqrt{13}}{\sin(60)}&=\frac{24}{\sin(\angle ADB)} \
\angle ADB &= 106.102113751986^\circ
\end{align*}
$$
I would like someone to check my answer before continuing.

thomas5267 · Answer

Something is wrong, not a clue where.

thomas5267 · Answer

A is aprrox. 11.529227073966273610794264223273466697365464574754 cm.

thomas5267 · Answer

B is approx. 16.102113751986015283606850794415244219216582587655 degrees.

thomas5267 · Answer

C is $24\sqrt{13}$.

thomas5267 · Answer

@Callisto Am I right?

callisto · Answer

A and B are correct!!!! Maybe you need to do C again :(

thomas5267 · Answer

C is $\frac{24}{\sqrt{13}}$.

callisto · Answer

Not really... But quite close though

thomas5267 · Answer

What is the answer then?

callisto · Answer

6.46, or 84/13