Question

@thomas5267 Here comes your problem~

Answer 1

a4.59552
b63.56222585
c9.5251563639

Answer 2

AE is \(3\sqrt{12}\).

Answer 3

@wumbo All are incorrect
@thomas5267 Hmm.. not correct neither

Answer 4

Isn't that point E bisects BC?

Answer 5

Yes

Answer 6

Sorry, I type the wrong answer, it should be \(12\sqrt{3}\).

Answer 7

Yes :)

Answer 8

Have to go now~ I'll come and check again tomorrow :)
Have fun!!!!

Answer 9

\[
\begin{align*}
AD&=\sqrt{(12\sqrt{3})^2+6^2} \\
AD&=6\sqrt{13}
\end{align*}
\]
\[
\begin{align*}
\frac{6\sqrt{13}}{\sin(60)}&=\frac{24}{\sin(\angle ADB)} \\
\angle ADB &= 106.102113751986^\circ
\end{align*}
\]
I would like someone to check my answer before continuing.

Answer 10

Something is wrong, not a clue where.

Answer 11

A is aprrox. 11.529227073966273610794264223273466697365464574754 cm.

Answer 12

B is approx. 16.102113751986015283606850794415244219216582587655 degrees.

Answer 13

C is \(24\sqrt{13}\).

Answer 14

@Callisto Am I right?

Answer 15

A and B are correct!!!! Maybe you need to do C again :(

Answer 16

C is \(\frac{24}{\sqrt{13}}\).

Answer 17

Not really... But quite close though

Answer 18

What is the answer then?

Answer 19

6.46, or 84/13