does anyone know how to do simplifying radical expressions?
Yup
can you help me with this chapter
\[\sqrt{36}-\sqrt{100}\]
is it -4
The general rule for the square root of a perfect square is: \[\sqrt{a^2} = a\] since a x a = a^2 In this case, you have \[\sqrt{36} \space \text{and} \space \sqrt{100}\] \[\sqrt{36} \space \text{can be re-written as} \sqrt{6^2} \space \text{since} \space 6 \times 6 = 36\]\[\sqrt{100} \space \text{can be re-written as} \space \sqrt{10^2} \space \text{since} 10 \times 10 = 100\]
So: \[\sqrt{36} - \sqrt{100} = \sqrt{6^2} - \sqrt{100} = 6 - 10 = -4\]. You are correct.
ok how abot this one \[-2\sqrt{48}+3\sqrt{75}\]
thanks
For this one there are a couple of things to know. First, you'll need to extract the perfect square from the number under the root. This will require awareness of what the perfect squares are as well as the ability to actually extract the square from the number under the root. Furthermore you'll have to be familiar with a particular rule of radicals that I will show you. The perfect squares up to 20 are 1, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, 144, 169, 196, 225, 256, 289, 324, 361, 400 Now to extract the perfect root from a number like 48 for instance: You perform the following: 1. First divide by 2 2. Then divide by 3 3. Then divide by 4 4. Then divide by 5. 5. Then divide by n. where n = the next number in the sequence, but stop when you see a perfect square. For instance, 48 divided by 3 = 16 and 16 is a perfect square. Therefore, re-write 48 as 16 x 3. The next thing you will need to know is the radical rules to apply for this particular problem. The general rule for radical roots is \[\sqrt{ab} = \sqrt{a \times b} = \sqrt{a} \times \sqrt{b}\] In this case we have: \[\sqrt{48} = \sqrt{16 \times 3} = \sqrt{16} \times \sqrt{3}\] Which you know the square root of 16 is 4. I hope that helps you a little bit.
@mandy86
Since you already figured out the answer, I see no need for further explanation.
ohhhh i know this answer! :D
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