Ask your own question, for FREE!
Mathematics 14 Online
OpenStudy (anonymous):

i need help on this question please

OpenStudy (anonymous):

\[\sqrt[3]{16}+4\sqrt[3]{54}\]

hero (hero):

Mandy, go back to your previous problem please.

OpenStudy (anonymous):

i already figured out thanks

hero (hero):

So you don't really need help with this chapter then. I just typed up an essay.

OpenStudy (anonymous):

no but i do with this one. im sorry about that

OpenStudy (anonymous):

can i show you what i got so far so you dont have to type it all

hero (hero):

Hint: \[\sqrt[3]{16}=\sqrt[3]{8} \dot\ \sqrt[3]{2}\]\[\sqrt[3]{54} = \sqrt[3]{27} \dot\ \sqrt[3]{2}\]

OpenStudy (anonymous):

\[3\sqrt{16}+4\sqrt[3]{54}\] \[\sqrt[3]{8}*4\sqrt[3]{2}\] 8=2*2*2 \[2\sqrt[3]{2}+4\sqrt[3]{2}\] \[6\sqrt[3]{2}\]

hero (hero):

You kinda skipped something

OpenStudy (anonymous):

\[4\sqrt[3]{27*2}\] \[4\sqrt[3]{27} *\sqrt[3]{2}\] then im stuck

hero (hero):

Okay, I will show you the steps since you have some kind of idea of what is going on

OpenStudy (anonymous):

thanks

hero (hero):

\[3\sqrt[3]{16} + 4\sqrt[3]{54} \]\[3 \dot\ \sqrt[3]{8} \dot\ \sqrt[3]{2} + 4 \dot\ \sqrt[3]{27} \dot\ \sqrt[3]{2} \]\[3 \dot\ 2 \dot\ \sqrt[3]{2} + 4\dot\ 3 \sqrt[3]{2}\]\[6 \sqrt[3]{2} + 12\sqrt[3]{2}\]

hero (hero):

I see that your initial approach was correct. It was just the way that you presented the steps wasn't very clear.

hero (hero):

But also that what I posted isn't the very last step

hero (hero):

You can actually factor out the cube root 2

hero (hero):

\[\sqrt[3]{2}(6 + 12) = \sqrt[3]{2}(18) = 18\sqrt[3]{2}\]

OpenStudy (anonymous):

ok but 27 is 3*3*3 so where did the other 3 go

OpenStudy (anonymous):

thats what i got stuck on

OpenStudy (anonymous):

oh i see thank you

hero (hero):

I was about to say...I thought the steps were pretty clear.

OpenStudy (anonymous):

but the answer in the bck of the book is \[14\sqrt[3]{2}\] that was my intial answer the one you got

hero (hero):

Maybe the back of the book is wrong?

hero (hero):

Double check and see if you have the original question posted correctly.

OpenStudy (anonymous):

hold on

OpenStudy (anonymous):

you put it wrong there is not 3 before the first one with 16

OpenStudy (anonymous):

go up to my first respones

OpenStudy (anonymous):

i forgot to put the 3 in the root too

hero (hero):

I was going with the latter one you posted where there WAS a three.

hero (hero):

So it is 14 cube root 2...okay

hero (hero):

The steps are still the same just don't multiply by 3

OpenStudy (anonymous):

thank you i understand it now

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!