i need help on this question please
\[\sqrt[3]{16}+4\sqrt[3]{54}\]
Mandy, go back to your previous problem please.
i already figured out thanks
So you don't really need help with this chapter then. I just typed up an essay.
no but i do with this one. im sorry about that
can i show you what i got so far so you dont have to type it all
Hint: \[\sqrt[3]{16}=\sqrt[3]{8} \dot\ \sqrt[3]{2}\]\[\sqrt[3]{54} = \sqrt[3]{27} \dot\ \sqrt[3]{2}\]
\[3\sqrt{16}+4\sqrt[3]{54}\] \[\sqrt[3]{8}*4\sqrt[3]{2}\] 8=2*2*2 \[2\sqrt[3]{2}+4\sqrt[3]{2}\] \[6\sqrt[3]{2}\]
You kinda skipped something
\[4\sqrt[3]{27*2}\] \[4\sqrt[3]{27} *\sqrt[3]{2}\] then im stuck
Okay, I will show you the steps since you have some kind of idea of what is going on
thanks
\[3\sqrt[3]{16} + 4\sqrt[3]{54} \]\[3 \dot\ \sqrt[3]{8} \dot\ \sqrt[3]{2} + 4 \dot\ \sqrt[3]{27} \dot\ \sqrt[3]{2} \]\[3 \dot\ 2 \dot\ \sqrt[3]{2} + 4\dot\ 3 \sqrt[3]{2}\]\[6 \sqrt[3]{2} + 12\sqrt[3]{2}\]
I see that your initial approach was correct. It was just the way that you presented the steps wasn't very clear.
But also that what I posted isn't the very last step
You can actually factor out the cube root 2
\[\sqrt[3]{2}(6 + 12) = \sqrt[3]{2}(18) = 18\sqrt[3]{2}\]
ok but 27 is 3*3*3 so where did the other 3 go
thats what i got stuck on
oh i see thank you
I was about to say...I thought the steps were pretty clear.
but the answer in the bck of the book is \[14\sqrt[3]{2}\] that was my intial answer the one you got
Maybe the back of the book is wrong?
Double check and see if you have the original question posted correctly.
hold on
you put it wrong there is not 3 before the first one with 16
go up to my first respones
i forgot to put the 3 in the root too
I was going with the latter one you posted where there WAS a three.
So it is 14 cube root 2...okay
The steps are still the same just don't multiply by 3
thank you i understand it now
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