i need more help!

Question

i need more help!

anonymous · Answer

$$\sqrt[3]{x^2y} - \sqrt[3]{8x^2y}$$

jhonyy9 · Answer

there are squareroots every two ?

jhonyy9 · Answer

???

anonymous · Answer

the x's are sr

hero · Answer

Hint: 

This is easier than you think

anonymous · Answer

teh aanswer is 3

hero · Answer

negative

anonymous · Answer

-3

hero · Answer

Alex, why don't you show your steps

hero · Answer

I don't agree that it's negative 3 either

anonymous · Answer

me either

anonymous · Answer

what do you have?

hero · Answer

Hint @ALEX_PERSAUD 

Whatever I have, it's even close to -3

anonymous · Answer

$$-\sqrt[3]{x^2y}$$

hero · Answer

^that is what I have

anonymous · Answer

hehe i look in the back of the book but i dont know how they got it

hero · Answer

@Mandy86 , did you take my advice or did you get the computer answer?

hero · Answer

That's weak

hero · Answer

You shouldn't have posted that

anonymous · Answer

what me ?

hero · Answer

Because now, I'm not interested in showing you how to get there anymore

hero · Answer

Because now that you have the answer, I'm convinced that you can figure out how to get there yourself.

anonymous · Answer

fine but i just need to the step and when i know the answer i know that im doing it right or wrong It helps me more than oyu think

hero · Answer

I will only tell you this: 
1. If the index of the root is bigger than the exponent under the root, then you cannot reduce the expression any further. 

2. Obviously the cube root of eight is two, so that's pretty much the only thing you can cube root. 

3. So once you do that, you'll be left with two expressions with like terms. You can add or subtract like terms.

anonymous · Answer

but you can split them apart

hero · Answer

Yes, you can split them apart, however, for the sake of simplicity, you only need to split the numerical cube root of 8 from the cube roots of the variables.

anonymous · Answer

$$\sqrt[3]{(8x^3y)xy}$$

hero · Answer

It goes back to a rule that I showed you earlier: 
$$\sqrt[n]{ab} = \sqrt[n]{a} \times \sqrt[n]{b}$$

In this case n = 3, a = 8, b = x^2y

hero · Answer

The last thing you posted is not correct

anonymous · Answer

oh im trying to do what the books says in the example to confusing

hero · Answer

Read the totality of everything I posted and you should be able to figure it out.

anonymous · Answer

so 8= 2*4 x^4=x^2 y^2 =y  
so $$\sqrt[3]{xy^2} -4\sqrt[3]{x^2y}$$

hero · Answer

1. You posted the first expression incorrectly. 
2. The CUBE ROOT of 8 is 2, not 4 because 2 x 2 x 2 = 8

anonymous · Answer

oops im doing the wrong question

hero · Answer

Did you figure it out?

anonymous · Answer

yes

hero · Answer

I'm amazed that it took you so long. :P

anonymous · Answer

i was fixing lunch to

anonymous · Answer

In the second term, the cube root of 8 is 2, therefore you must take out the 2 of the equation, leaving it to be $$\sqrt[3]{x^2y} - 2\sqrt[3]{x^2y}$$ after that you subtract the two terms, leaving the answer to be $$-\sqrt[3]{x^2y}$$ :)