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How can I prove that que ∫sen(kx) = (-cos(kx))/k+C in details!!
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Your question is to prove \[\int \sin (kx) dx= -\frac{\cos kx}{k}+c\]???
Yes
Do you know this? \[\int \sin x=-\cos x +c\]
yes
Our integral is \[\int \sin kx\ dx\] Let's substitute kx=u so \[kdx=du\] or \[dx=\frac{du}{k}\] Our integral changes now to \[\int \sin (u) \frac{du}{k}\] k is constant so it'll come out of the integral \[\frac{1}{k}\int \sin (u) \du\] Now it's easy, integrating we get \[-\frac{\cos u}{k}+c\] put u =kx We get \[-\frac{\cos kx}{k}+c\]
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