Question

quadratic

Answer 1

The value of p for which both of the roots of the equation 4x^2-20px+(25p^2+15p-66)=0 are less than 2,lies in interval?

Answer 2

Well we have two real roots in the interval\[\left({1 \over 10}(-3-\sqrt{673}), \;\;{1 \over 10}(3-\sqrt{673}) \right)\]

Answer 3

hmm ..i need the method of getting the interval

Answer 4

To have a real root, we need the discriminant to be positive, in this case the discriminant is \[20^2 -4(25p^2+15p-66)\]If you use the quadratic formula on this you find p has to be in the interval I posted above.

Answer 5

@amistre64 , @phi , @Ishaan94

Answer 6

Now we need to check which roots are less than 2.

Answer 7

hw?

Answer 8

Not sure how to do that yet. I'll keep trying.

Answer 9

is it even possible??
20/8 +- discriminant

Answer 10

its possible

Answer 11

for both root to be less than 2 ... since one discriminant will be positive.

Answer 12

I'm going to agree with experimentX. I can't find any values of p that would work.

Answer 13

hmmmmmmmmm