Solve 5^(x + 5 )= 9x Solving Exponential Equations with Unequal Bases

Question

anonymous · Answer

answer options: 
x ≈ 13.69
		
x ≈ 0.07
		
x ≈ –0.28
		
x ≈ –3.63

amistre64 · Answer

the answers dont explain how ....

amistre64 · Answer

youre best bet might be to get them to speak in natural logs and work it from that angle

amistre64 · Answer

is that a 9x or a 9^x ?

anonymous · Answer

a 9^x sorry wrote it wrong.

amistre64 · Answer

5^(x + 5 )= 9^x  ; ln it all

ln(5^(x + 5 ))= ln(9^x)  ; lns pull out exponents

(x+5) ln(5)= x ln(9)  ; get the xs to one side and the rest to the other

(x+5)/x = ln(9)/ln(5)  ; assuming x not equal 0

amistre64 · Answer

1+5/x = ln ...

5/x = ln ....

5/ln ... = x

amistre64 · Answer

ugh, i forgot to type in the -1 :/  bad fingers bad!!

amistre64 · Answer

1+5/x = ln ...

5/x = ln .... - 1

5/ln .. - 1 = x

anonymous · Answer

you need to take log of both sides and then try to solve for x using the properties of log