what's the integral: ∫cos(x^2)
That's a pretty damn hard indefinite integral, IIRC. It's a Fresnel. And I don't how to solve it analytically. Check: http://mathworld.wolfram.com/FresnelIntegrals.html
use power series
Yeah, that's what I was going to post, :-). You can approximate it fairly easily to a power series, but to actually solve the integral analytically is near impossible, I think.
it is not 'near impossible' it is impossible in terms of elementary functions :)
yeah, these need middle school functions ;)
yes...those are much more powerful ;)
Maybe even some undergrad functions also :-). So, I think that the original problem reduces to approximate it to a power series and integrating it.
I get it from wolfram... how can I simplefied it?
Like I said, from Wolfram you will get the Fresnel anallytical solution. Remember that the Maclaurin series for cosx is:\[\cos(x) = \sum_{0}^{\infty}((-1)^{n}x^{2n})/2n!\] Just plug in x^2 for x and you will have the series for cos(x^2). Integrate it, and voila, you got your integral :-)
oops, from n = 0 to infinity. A typo there.
Thank you!!!!
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