Question

Decompose into partial fractions:
(x^3+2)/(x^2-1)

Answer 1

\[\LARGE \frac{x^3+2}{x^2-1}=\frac{x^3+2}{(x-1)(x+1)}=\]
\[\LARGE {x^3+2\over x-1}\cdot {1\over x+1}=\left( {x^3\over x-1}+{2\over x-1 }\right)\cdot {1\over x+1} \]
I don't know if this is what you're asking for, if it's not, throw it away ;)

Answer 2

divide first

Answer 3

Its fine to the point\[(x^3+2)/(x-1)(x+1)\] but now I have to solve for \[(x^3+2)/(x-1)(x+1) = A/(x-1) + B/(x+1)\] want to check ifthe answers I got for A and B are correct

Answer 4

divide first to get
\[x+\frac{x+2}{(x+1)(x-1)}\]

Answer 5

the degree of the numerator is bigger than the degree of the denominator,so before trying partial fraction decomposition divide to get a quotient and a remainder. then pfd for the remainder

Answer 6

what experimentx said before he/she deleted it

Answer 7

\[\frac{x^3+2}{x^2-1}=x+\frac{3}{2 (x-1)}-\frac{1}{2 (x+1)} \]

Answer 8

Thanks that helped alot

Answer 9

@satellite73 I will always remember your words before I attempt a partial fraction question again

Answer 10

glad to help