Question

(8x^3+4x^2+100)/(2x+5)

Answer 1

We have
\[ \frac{(8x^3+4x^2+100)}{(2x+5)}\]
We need to find the factors of \(8x^3+4x^2+100\), once we have the factors we'll have an easy road.
Are you here?

Answer 2

yes

Answer 3

We have
\[8x^3+4x^2+100\]
Generally cubic equations are not straight forward. But I have a feeling that we have one factor as 2x+5, as it's in the denominator. Let's check if I think right.
if 2x+5 is a factor then x=-5/2 will make \(8x^3+4x^2+100=0\)
Let's check
\[8x^3+4x^2+100\]
x=-5/2
\[8 ( -5/2)^3+4 (-5/2)^2+100\]
\[8*(-125/8)+4(+25/4)+100\]
\[-125+25+100=0\]
Wow I though right, so we have one factor as (2x+5). Did you get till here?????

Answer 4

i dont think so

Answer 5

Which part you don't understand?

Answer 6

wait.....never mind

Answer 7

Woah!! tell me, I'm here to help you!!!

Answer 8

its fine i got it

Answer 9

Okay so shall we proceed now?

Answer 10

i need help!!

Answer 11

on this question, i dont understand it