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4.5g of Iron (II) Phosphate reacts with 6.5g of molybdenum(IV) sulphide in a double displacement reaction. What is the theoretical yeild in grams of the product containing the sulphide ion in this reaction?
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Fe3(PO4)2 PbS2 so Fe3(PO4)2 + PbS2 -> Fe2S3 + Pb3(PO4)4
balane that please
oops my bad!!!! Fe3(PO4)2 + PbS2 -> FeS + Pb3(PO4)4
thank you !
it still needs balancing...
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