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OpenStudy (anonymous):
What is the simplified form of 5 over 3y minus 2 - 4 over 9 y-squared minus 4 ?
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OpenStudy (australopithecus):
(5/3y) - (2) - (4/9y) - (4)^(1/2)
You can use the trick I taught you to solve this
(5/3y)-(2(3y)/3y) - (4(3y)/9y(3y)) - ((3y)(4)^(1/2)/(3y))
OpenStudy (australopithecus):
note
(4)^(1/2) is the same as \[\sqrt{4}\]
OpenStudy (australopithecus):
so you have (5 - 2(3y) - 3y(4)^(1/2))(9y)/3y(9y) - (4(3y)/9y(3y))
OpenStudy (australopithecus):
=
9y(5 - 2(3y) - 3y(4)^(1/2)) - 4(3y))/3y(9y)
OpenStudy (australopithecus):
now you can just simplify
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OpenStudy (anonymous):
ok hold on im trying to catch up
OpenStudy (anonymous):
is it all over 3y/9y?
OpenStudy (australopithecus):
the denominator is 3y(9y)
OpenStudy (australopithecus):
the neumorator is
9y(5 - 2(3y) - 3y(4)^(1/2)) - 4(3y)
OpenStudy (australopithecus):
you have to distribute the 9y
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OpenStudy (anonymous):
so 21y over 27y^2
OpenStudy (australopithecus):
let me actually work it out :\
OpenStudy (australopithecus):
9y(5) - 2(3y)(9y) - 3y(9y)2 - 4(3y)
=
(33y - 108y^(2))/27y^(2)
OpenStudy (australopithecus):
so you have
33y/27y^(2) - 108y^(2)/27y^(2)
so you can simplify further
OpenStudy (anonymous):
|dw:1334871543217:dw|
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