How do I solve equations with variables on both sides
x + 1 = 0 x = -1
x + 1 -1 = 0-1
If you do the same thing to both sides of the equation the equation remains equal
lets try an example 3x + 1 = 2x + 3 we need terms in x on left and numbers on right first subtract 2x from each side 3x - 2x + 1 = 3 now subtract 1 from both sides 3x - 2x = 3 - 1 x = 2
note we could move terms in x to right and numbers to left - you get same result
is this what u r looking for?
Pretty much but my homework is sorta hard and i try to do thingz like this and ifind it difficult
how is it hard - more negative signs maybe?
yea...i have a prob that says -4b - 5 = 3b +9....and im in the 6th grade and my teach believez i kan do this 8th grade stuff and im trying but this subject is a weak spot
ok well similar to what i wrote before: lets remove the 3b from the right side by subtract 3b from both sides: -4b - 3b - 5 = 3b - 3b + 9 -7b - 5 = 9 now add 5 to both sides: -7b = 9 - 5 -7b = 4 now divide both sides by -7: b = 4 / -7 = -4/7 note you always have to perform any operation on an equation on both sides to keep the balance of the equation
sorry i made a mistake on line 7 - it should have been -7b = 9 + 5 and b then becomes 14/-7 = -2
ok wow thankz that helped...now i understand the river technique a lil better
good - yw
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