Y=2x^2-32
Find the x-intercepts of this equation how do u do that ?

Question

Y=2x^2-32
Find the x-intercepts of this equation how do  u do that ?

anonymous · Answer

Help some one :(

sburchette · Answer

x-intercepts of a function occur at values of x that cause y to equal zero.  To find x-intercepts, substitute 0 for y and solve for x.  

$$0=2x ^{2}-32 $$ 
$$32=2x ^{2}$$ (Add 32 to both sides)
$$x^2=16   $$ (divide both sides by 2)
$$\sqrt{x^2}=\pm \sqrt{16}$$ (Take the square root of both sides)
$$x=\pm4$$

Therefore, the x-intercepts of the function are 4 and -4. If you graph the function, you should see the curve intersect the x-axis at those values.  If you substitute 4 or -4 in for x, you should get 0.