Question

a 50 milliliter solution of acid and water contains 25% acid. how much water do you need to add in order to make a 10% acid solution?

Answer 1

Eh, I'm not good at this. I can tell you how I do it, but It's probaly not he most effiecient

Answer 2

50*0.25=0.1x

Answer 3

And that's assuming the 25% is by volume, not by weight

Answer 4

IF it's by weight, there is not enough info to do theproblem, so it's most likely by volume

Answer 5

Wait, 0.1 x is the total amount

Answer 6

50*0.25=0.1x
then subtract 50 from x

Answer 7

@iHeartYou ?

Answer 8

thanks

Answer 9

you have 50 ml which is 25% acid, so you have \(.25\times 50=12.5\) ml of acid
if you add say "x" amount of water you will have 50 + x ml of water and still have 12.5 ml of acid. you want this 12.5 ml of acid to be 10% of the total, so put \(.10(50+x)=12.5\) and solve for x

Answer 10

you should get \(5+.1x=12.5\) the subtract 5 to get \(.1x=7.5\) divide by .1 to get
\[x=7.5\div .1=75\div 1=75\] and so you need to add 75 ml of water

Answer 11

you people are very smart