Factor completely Remember to look first for a common factor. Check by multiplying. If a polynomial is prime, state this. 2x^3 − 40x^3 + 192x
2x(x^2-20x^2+91) 2x(x-17)(x-3)
by the way, I think your second term should be -40x^2
Never mind I misread the expression, it is simpler than I thought.
how do you mean?
well, usually, you would have ax^3 + bx^2+ cx. Like radar said, if it's really -40x^3, it looks a bit too simple, no?
i don't know. The book has it 2x^3 − 40x^3. So does having it minus equal -40?
The first two terms can be combined: (unless there is a typo) getting: -38x^3 + 192x -2x(19x^2-96)
so is factoring just combining "like" terms?
That is far as it goes, I think
If there are like terms, you should combine them, then factor out and common factors that exist in the expression.
you're too quick for me @radar ;-)
Normally the don/t have similar terms, that is why I misread it.lol.
I have slowed down to a stop!
thank you both! I think I understand it a tad better!
the problem wanted you to check to multiply your result. Do you want to check?
yes. How do I do that?
O.K. Here is why I think it is a typo. we had: -2x(19x^2-96) multiplying we get: -38x^3 + 192x The -38x^3 can be expressed as 2x^3-40x^3 + 192x looks like the original.
The reason I think it is a typo is the two terms which have the x^3 in them. I think the second term was meant to be x^2, but I stuck with what was given.
Not sure if it was a typo because it was from my book. But thank you. I appreciate all the help! I was just lost looking at it!
It is a confusing problem, good luck with them.
thank you! You rock!
You're welcome.
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