How do I prove this?????? 1 + tanx (tan(x/2)) = secx
\[1+\frac{\sin x}{\cos x}(\frac{1-\cos x}{\sin x})=1+\frac{1-\cos x}{\cos x}=\]
\[1+\frac{1}{\cos x}-\frac{\cos x}{\cos x}=1+\sec x-1=\sec x\]
I'm not understanding what you just did Could you explain?
I replaced tanx with sin/cos I replaces tan(x/2) with (1-cosx)/sinx I cancelled sinx from numerator and denominator I split the fraction into two fractions I replaced 1/cosx with secs. I replaced cosx/cosx with 1 I subtracted 1-1
Awesome, would this be the standard method for proving problems or is it just for this problem?
It would be standard form for proving identities.
So just to be clear I can use the steps you just provided for proving all identities?
No. Only the ideas transfers to another problem. The ideas of making the proper substitutions and simplifying and of working on one side only. Every problem is unique.
Ok
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