integral x(sqrt(1+x)) dx show me how to do with u substitution please
It's not real efficient to do this with u substitution. You wind up with the same thing you start off with. I'd just change the square root to a powered quantity and distribute.
can you show me how to do this then?
Yeah, let's just use u substitution anyway. With u substitution you want to rewrite the integral to an easier form to work with so try setting u=x+1.
i did that and it ends up so dx=du and x=u-1
Yes. So substitute those values back into the integral to get it in term of u, then distribute.
Then integrate with respect to u and when you're done, get the answer back in terms of x.
\[\int\limits_{}^{}\left( u-1 \right)\sqrt{u}du\] okay?
i dont know how to integrate that term
Yes. And you can rewrite the square root of u as u^(1/2). So then all you do is distribute that through (u-1).
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