Propane burns completely in excess oxygen. A mixture of 10cm^3 of propane and 80cm^3 of oxygen was sparked. The residual gases were cooled to room temperature. What is the final volume of residual gases?
I don't think we have enough information to solve for this. Is there additional information for the problem?
No. There's just an equation given. C3H8+5O2--->3CO2+4H2O
wht is residual volume?
I don't know. xP If I knew, why would I post it here?
i think its the volume of gas(product) formed according to the moles, i get 70 cm^3 is the answer...
But the book says it's 60. The products are CO2(g) and H20(l). What I think is that residual volume is the volume of leftover oxygen and the CO2 produced since when cooling is down, both of these will liquefy.
*cooling is done
And thus 30 cm^3 of oxygen plus 30cm^3 of C02 will give us 60 cm^3.
burns completely* did u read tht....
I read that. But it also says 'excess oxygen'.
okay wait
We need an EXPERT here. LOL. I'm not sure about my method too. xP
i think its correct...yes. excess means Oxygen is left, i calculated there were 30 cm^2 of oxygen and obviously 30 cm^2 of CO2
cm^3
yes sorry
But i think the next part is impossible to figure out. With out the mass of the substance we can't figure out the volume, presure would be nice also.
assume root condition before and after in same condition ratio of volume =ratio of moles C3H8+5O2--->3CO2+4H2O initial 10 80 0 0 reacts/produse -10 -50 +30 +40 final 0 30 30 40 but in room cond H2O is liquid so Volume of gases 30+30=60
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