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Chemistry 17 Online
OpenStudy (anonymous):

Propane burns completely in excess oxygen. A mixture of 10cm^3 of propane and 80cm^3 of oxygen was sparked. The residual gases were cooled to room temperature. What is the final volume of residual gases?

OpenStudy (anonymous):

I don't think we have enough information to solve for this. Is there additional information for the problem?

OpenStudy (anonymous):

No. There's just an equation given. C3H8+5O2--->3CO2+4H2O

OpenStudy (anonymous):

wht is residual volume?

OpenStudy (anonymous):

I don't know. xP If I knew, why would I post it here?

OpenStudy (anonymous):

i think its the volume of gas(product) formed according to the moles, i get 70 cm^3 is the answer...

OpenStudy (anonymous):

But the book says it's 60. The products are CO2(g) and H20(l). What I think is that residual volume is the volume of leftover oxygen and the CO2 produced since when cooling is down, both of these will liquefy.

OpenStudy (anonymous):

*cooling is done

OpenStudy (anonymous):

And thus 30 cm^3 of oxygen plus 30cm^3 of C02 will give us 60 cm^3.

OpenStudy (anonymous):

burns completely* did u read tht....

OpenStudy (anonymous):

I read that. But it also says 'excess oxygen'.

OpenStudy (anonymous):

okay wait

OpenStudy (anonymous):

We need an EXPERT here. LOL. I'm not sure about my method too. xP

OpenStudy (anonymous):

i think its correct...yes. excess means Oxygen is left, i calculated there were 30 cm^2 of oxygen and obviously 30 cm^2 of CO2

OpenStudy (anonymous):

cm^3

OpenStudy (anonymous):

yes sorry

OpenStudy (anonymous):

But i think the next part is impossible to figure out. With out the mass of the substance we can't figure out the volume, presure would be nice also.

OpenStudy (mos1635):

assume root condition before and after in same condition ratio of volume =ratio of moles C3H8+5O2--->3CO2+4H2O initial 10 80 0 0 reacts/produse -10 -50 +30 +40 final 0 30 30 40 but in room cond H2O is liquid so Volume of gases 30+30=60

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