Find The equation of the tangent to the curve x^2+y^2=25 at x=3
tangent to the curve? That calls for derivative.
No....this is a circle with radius 5 and center at origin.
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first you need to differentiate with respect to x 2x + 2y*dy/dx = 0 - right GT - thers an easier way
You can find the equation of line between 0,0 and 3,4 and then find its perpendicular line at 3,4. That is one way.
Wait so I'm wrong? We can't use derivatives to solve this?
You could, I suppose.
Depends on whether the student was taught such stuff for this topic.
GUys ,can i have only one right answer ?!!
How would you start the problem @Eyad
I would start it by subs. x in the equation , so i can get (y ).. and then make a dervative and work on the law and get the slope by y-y1\x-x1 and then get the equation ?!
that what ma friend told me ?!!!
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