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Mathematics 9 Online
OpenStudy (anonymous):

Find The equation of the tangent to the curve x^2+y^2=25 at x=3

OpenStudy (anonymous):

tangent to the curve? That calls for derivative.

OpenStudy (anonymous):

No....this is a circle with radius 5 and center at origin.

OpenStudy (anonymous):

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OpenStudy (cwrw238):

first you need to differentiate with respect to x 2x + 2y*dy/dx = 0 - right GT - thers an easier way

OpenStudy (anonymous):

You can find the equation of line between 0,0 and 3,4 and then find its perpendicular line at 3,4. That is one way.

OpenStudy (anonymous):

Wait so I'm wrong? We can't use derivatives to solve this?

OpenStudy (anonymous):

You could, I suppose.

OpenStudy (anonymous):

Depends on whether the student was taught such stuff for this topic.

OpenStudy (anonymous):

GUys ,can i have only one right answer ?!!

OpenStudy (anonymous):

How would you start the problem @Eyad

OpenStudy (anonymous):

I would start it by subs. x in the equation , so i can get (y ).. and then make a dervative and work on the law and get the slope by y-y1\x-x1 and then get the equation ?!

OpenStudy (anonymous):

that what ma friend told me ?!!!

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