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Mathematics 11 Online
OpenStudy (anonymous):

for 2 sets A and B prove P(A)=P(B) implies A=B

OpenStudy (zarkon):

I assume P(A) is the powerset of A

OpenStudy (anonymous):

yes it is @Zarkon

OpenStudy (zarkon):

you know \[A\in P(A)\]correct?

OpenStudy (anonymous):

yes

OpenStudy (zarkon):

and since P(A)=P(B) then \[A\in P(B)\] right?

OpenStudy (anonymous):

yeess...

OpenStudy (zarkon):

P(B) is all the subsets of B therefore \[A\subseteq B\]

OpenStudy (anonymous):

yeah

OpenStudy (zarkon):

similarly \[B\subseteq A\] thus \[A=B\]

OpenStudy (anonymous):

i get it thanks:)

OpenStudy (zarkon):

np

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