1296^2n=216^n+10
can you first give the prime factorization for 1296 and 216 for me?
do you need help?
nevermind! sorry! but can you help with this one? \[6^{6n}\le1/1296\]
yes... notice that 1296 came up again.... i'm going to ask you the same thing... give me the prime facorization of 1296
i am very bad at math! what do you mean by prime factorization?
in order to solve your problem we need to write 1296 as some power of 6. having the prime factorization greatly helps...
can you write 1296 as a power of 6?
i don't think you can do this problem by elementary methods. where does it come from? this is very hard to solve
or asnswer this: 6^x = 1296 , what's x?
n would be four. i am doing classes online and this came up. my answer choices are \[n \le -24, n \le -2/3, n \le -2/3, or n \le -5/6\]
i can tell you the answer but that's not the procedure here. i am willing to help you get the answer though if you'd put in the time...
well i have 35 minutes, and i still need help on another problem. please make my life a little easier
\[6^{6n }\le\frac{1}{1296}\] \[6^{6n}\le6^{-4}\] \[6n \le-4\] \[n \le\frac{-2}{3}\]
thanks guys but i forgot to say this test is timed! it just ran out ): i appreciate it though!
Are you sure you posted the very first problem right? Is the +10 the right number?
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