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Mathematics 15 Online
OpenStudy (anonymous):

1296^2n=216^n+10

OpenStudy (anonymous):

can you first give the prime factorization for 1296 and 216 for me?

OpenStudy (anonymous):

do you need help?

OpenStudy (anonymous):

nevermind! sorry! but can you help with this one? \[6^{6n}\le1/1296\]

OpenStudy (anonymous):

yes... notice that 1296 came up again.... i'm going to ask you the same thing... give me the prime facorization of 1296

OpenStudy (anonymous):

i am very bad at math! what do you mean by prime factorization?

OpenStudy (anonymous):

in order to solve your problem we need to write 1296 as some power of 6. having the prime factorization greatly helps...

OpenStudy (anonymous):

can you write 1296 as a power of 6?

OpenStudy (anonymous):

i don't think you can do this problem by elementary methods. where does it come from? this is very hard to solve

OpenStudy (anonymous):

or asnswer this: 6^x = 1296 , what's x?

OpenStudy (anonymous):

n would be four. i am doing classes online and this came up. my answer choices are \[n \le -24, n \le -2/3, n \le -2/3, or n \le -5/6\]

OpenStudy (anonymous):

i can tell you the answer but that's not the procedure here. i am willing to help you get the answer though if you'd put in the time...

OpenStudy (anonymous):

well i have 35 minutes, and i still need help on another problem. please make my life a little easier

OpenStudy (mertsj):

\[6^{6n }\le\frac{1}{1296}\] \[6^{6n}\le6^{-4}\] \[6n \le-4\] \[n \le\frac{-2}{3}\]

OpenStudy (anonymous):

thanks guys but i forgot to say this test is timed! it just ran out ): i appreciate it though!

OpenStudy (mertsj):

Are you sure you posted the very first problem right? Is the +10 the right number?

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