Question

problem is attached

Answer 1

\[560+8.76^y=7369\] like that ?

Answer 2

yes

Answer 3

first subtract 560 from both sides to get
\[8.76^y=6809\] then using the change of base formula you get
\[y=\frac{\ln(6809}{\ln(8.76)}\] then use a calculator

Answer 4

i don't get it

Answer 5

you have a variable that is in the exponent, and you are trying to solve for that variable. you have to use logs to do it

Answer 6

in order to solve
\[b^x=A\] for x, you use
\[x=\frac{\ln(A)}{\ln(b)}\] the log of the total divided by the log of the base

Answer 7

in your example, \(A=6809\) and \(b=8.76\) because you have
\[8.76^y=6809\] therefore
\[y=\frac{\ln(6809)}{\ln(8.76)}\]