Question

If f(x)= -4x^2+12x-9 and g(x)= -9-3x+x^2,find 6f(1/2)-2g(2). Please show me step by step.

Answer 1

f(x)= -4x^2+12x-9



f(1/2)= -4(1/2)^2+12(1/2)-9



f(1/2)= -4(1/4)+12(1/2)-9



f(1/2)= -4/4+12/2-9



f(1/2)= -1+6-9



f(1/2)= -4

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g(x) = -9-3x+x^2



g(2) = -9-3(2)+(2)^2



g(2) = -9-3(2)+4



g(2) = -9-6+4



g(2) = -11


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6*f(1/2) - 2*g(2)



6*(-4) - 2*(-11)



-24 + 22



-2



So 6*f(1/2) - 2*g(2) = -2

Answer 2

First off: You have to plug 1/2 into f(x).
f(1/2)= -4*(1/2)^2+12(1/2)-9
Then, you need to plug 2 into g(x):
g(2)=-9-3(2)+(2)^2
Next you need to put everything together.
6*[f(1/2)= -4*(1/2)^2+12(1/2)-9]-2*[g(2)=-9-3(2)+(2)^2]
So you solve what's inside the parentheses
And then you multiply what ever you get inside by the numbers outside of the parentheses
And finally you subtract the numbers.
And your final answer is -2