Question

5. [9.01] The graph of which equation is shown below?
https://www.connexus.com/content/media/527934-762011-84933-AM-1383066450.png

(4 points)
y = −x2 + 6x − 5
y = −x2 − 6x − 5
y = x2 + 6x − 5
y = x2 − 6x − 5

Answer 1

please help :)

Answer 2

I think it's one of the first two because it opens down. I could be wrong though

Answer 3

The link is to the image

Answer 4

maximum point is -3,4

Answer 5

-5,0 and -1,0 are the x intercepts

Answer 6

-2, 3 and -4,3 are two other points

Answer 7

Oh, didn't see :s
So, we know that a parabola's equation is y = a(x-h)^2 + k
You plug the maximum points in (h,k)
and a point in (x,y)
So it would be 3 = a(-2 - -3)^2 + 4
3 = a(-2+3)^2 +4
3 = a + 4
a = 3-4
a = -1

And you put a back
y = -1(x+3)^2 + 4
Then you need the general form
y = -(x+3)^2 + 4
y = -(x^2 + 6x + 9) +4
y = -x^2-6x-9+4
y = -x^2 - 6x -5

B) would be the answer :)

Answer 8

OK thanks but Im still a little lost lol

Answer 9

In fact, I just used the basic form for a parabola and plugged stuffs into it
since (h,k) is the maximum point, and (x,y) could be anything, I did the above ^ :)

Answer 10

okay I have another question if thats okay (i get it now :D)

Answer 11

6. [9.02] What are the solutions of x2 − 3x − 18 = 0? (4 points)
x = 3, x = −6
x = −3, x = 6
x = 3, x = 6
x = −3, x = −6

Im pretty sure you just solve and get x=? then plug that into one of the x's and whatever you get next is the other x= .right?

Answer 12

Nope, you use the quadratic formula ;)

Answer 13

can you help?