Find the length of the longer diagonal of the rhombus with sides of 6cm and acute angles of 40 degrees.
nvrmind
Umm ok.
I guess what I have to do is divide the rhombus into two triangles. Then what do I do?
And I guess the hypotenuse of one these triangles would be the diaganol I'm looking for correct?
|dw:1334970582291:dw|
the length of the longer diagonal is 2y. since the diagonals of a rhombus are perpendicular and bisect each other we can just focus on 1 triangle. notice that cos(20 degrees) = y/6. so y=6*cos(20 degrees). the length of the longer diagonal is therefore 2y = 2*6cos(20 degrees) = 12*cos(20 degrees)
All in all it was just a brick in the wall...
Haha.
Woah man thanks. That helps. For some reason I thought it would be like this.|dw:1334971083848:dw|
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