Find the maximum or minimum of: f(x) = x2 + 4x + 4. What is the value of x that produces the maximum (or minimum)
f(x)=x^2+16x
By examining this function, we can see that it will have a minimum because a positive x^2 term will open upward. A min will occur where the slope of the tangent line to the curve is 0, so we can differentiate f(x) to obtain \[f'(x)=2x+4\] Setting this equal to zero and solving we get\[x=-2\] So the function has a critical number at x=-2 and likely an extremum there as well. We can take the derivative at t value less than the critical number and at a value greater than the critical number to determine whether the graph is increasing or decreasing. \[f'(-3)=-2\]\[f'(0)=4\] So the function is decreasing to the left of the critical number and decreasing to the right. From this we can conclude that there is a minimum at the point (-2,0)
Correction: I meant to say that the function is increasing to the right of the critical number
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