Question

HELP PLEASE!!!!!!!!!!!
Find the values of b such that the system
x^2 + y^2 = 9
y = x + b
has two solutions. (Enter your answer using interval notation.)

Answer 1

Rewriting in terms of x, we get:\[2x^{2} + 2bx + (b^{2} - 9) = 0\]Remember from the quadratic formula that:\[\Delta = \sqrt{b^{2} - 4ac} > 0\]for the equation to have two distinct solutions. So, we get:\[\Delta = (2b)^{2} - 8(b^{2} - 9) > 0\]and you have to solve for b. Can you try it now?

Answer 2

id just go back to the picture ....

Answer 3

+- 3sqrt(2) is what i would bet on it

Answer 4

I tried, didn't work(