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decompose 6x/(x-4)(x+2) into partial fractions
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\[(−6/x+2)+12/(x+4)\]
\[\rightarrow \frac{A}{x-4}+\frac{B}{x+2} = \frac{6x}{(x-4)(x+2)}\] A(x+2) + B(x-4) = 6x A+B = 6 2A-4B = 0 --> A=4 --> B=2
@RaphaelFilgueiras, its (x-4) not (x+4)
Thank you!
yes i do with x+ 4!
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@ananaa you're fine with the next step?
I thought so...
Do you want to check your result?
next step? oh is this linked to a larger problem involving an integral
how do you check your results?
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Just post your result, so we can help you :)
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